105=(x^2-x)/2

Solution for 105=(x^2-x)/2 equation:

105=(x^2-x)/2

We move all terms to the left:

105-((x^2-x)/2)=0

We multiply all the terms by the denominator


-((x^2-x)+105*2)=0


We calculate terms in parentheses: -((x^2-x)+105*2), so:

(x^2-x)+105*2

We add all the numbers together, and all the variables

(x^2-x)+210

We get rid of parentheses

x^2-x+210

We add all the numbers together, and all the variables

x^2-1x+210

Back to the equation:

-(x^2-1x+210)


We get rid of parentheses

-x^2+1x-210=0

We add all the numbers together, and all the variables

-1x^2+x-210=0

a = -1; b = 1; c = -210;
Δ = b2-4ac
Δ = 12-4·(-1)·(-210)
Δ = -839
Delta is less than zero, so there is no solution for the equation